20x^2-36x=-8

Solution for 20x^2-36x=-8 equation:

20x^2-36x=-8

We move all terms to the left:

20x^2-36x-(-8)=0

We add all the numbers together, and all the variables

20x^2-36x+8=0

a = 20; b = -36; c = +8;
Δ = b2-4ac
Δ = -362-4·20·8
Δ = 656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{656}=\sqrt{16*41}=\sqrt{16}*\sqrt{41}=4\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{41}}{2*20}=\frac{36-4\sqrt{41}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{41}}{2*20}=\frac{36+4\sqrt{41}}{40}
$